SOLUTION: it say to use the substitutuon
y=x+2
2x+y=8
x+y=3
3x+y=3
3x-y=9
2x+y=6
I hope you ca help I need to know how to do this for my exam
Algebra ->
Linear-equations
-> SOLUTION: it say to use the substitutuon
y=x+2
2x+y=8
x+y=3
3x+y=3
3x-y=9
2x+y=6
I hope you ca help I need to know how to do this for my exam
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I hope you ca help I need to know how to do this for my examine Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! y=x+2
2x+y=8
Look at the first equation. (y = x + 2)-- has a solutions of
2x + y = 8
2x + x + 2 = 8
3x = 6
x = 2
So ....
y = x + 2
y = 2 + 2
y = 4
(2,4) is your solution! That is where the two line's meet.
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x+y=3
3x+y=3
Change the first equation to by subtracting , so is equal to
3x + y = 3
3x + -x + 3 = 3
2x = 0
x = 0
So ....
x + y = 3
0 + y = 3
y = 3
(0,3) is your solution! That is where the two line's meet.
------
3x-y=9
2x+y=6
Change the second equation to by subtracting , so is equal to
3x - y = 9
3x - (-2x + 6) = 9
3x + 2x - 6 = 9
5x = 15
x = 3
So ....
2x + y = 6
2(3) + y = 6
6 + y = 6
y = 0
(3,0) is your solution! That is where the two line's meet.
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