SOLUTION: find the center and the radius of the cirlce (x+4)^2+y^2=100

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the center and the radius of the cirlce (x+4)^2+y^2=100      Log On


   



Question 415814: find the center and the radius of the cirlce (x+4)^2+y^2=100
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
cirlce (x+4)^2+y^2=100 |c(-4,0) and r = 10