SOLUTION: the sum of three numbers is 100. find the numbers if the second number is 10 more than twice the first and the third is ten less than sum of the first two
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Question 415702: the sum of three numbers is 100. find the numbers if the second number is 10 more than twice the first and the third is ten less than sum of the first two Found 2 solutions by ewatrrr, htmentor:Answer by ewatrrr(24785) (Show Source):
Hi
Let x, (2x+10) and (x + 2 x + 10 -10) represent the three numbers
Question states***
x + (2x+10) +(3x) = 100
Solving for x
6x = 90
x = 15 | Numbers are: 15, 40, 45
CHECKING our Answer***
15 + 40 + 45 = 100
You can put this solution on YOUR website! x+y+z=100 (1)
y=2x+10 (2) 2nd number (y) is (=) 10 more (+) than twice (x) the 1st
z=x+y-10 (3) 3rd number (z) is 10 less (-) than sum of first two (x+y)
Solve for x+y in (3) -> x+y=z+10
Insert into (1) -> (z+10)+z=100 -> 2z+10=100 -> z=45
From (1) x+y=100-z -> x+y=55 -> y=55-x
Subtitute into (2) -> 55-x=2x+10 -> 3x=45 -> x=15
Since x+y+z=100 -> 15+y+45=100 -> y=40
Ans: x=15,y=40,z=45
