SOLUTION: This problem seems to be straigt forward, i just cannot work it. I would appreciate the help.
JCULP
Bob walks 5 mph,then jogs 9 mph for one hour. The total distance is 6 mi
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-> SOLUTION: This problem seems to be straigt forward, i just cannot work it. I would appreciate the help.
JCULP
Bob walks 5 mph,then jogs 9 mph for one hour. The total distance is 6 mi
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You can put this solution on YOUR website! Bob walks 5 mph,then jogs 9 mph for one hour. The total distance is 6 miles.
How far did he walk.
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Walk DATA:
rate = 5 mph ; time = x hrs ; distance = 5x miles
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Jog DATA:
rate = 9 mph ; time = 1-x hrs ; distance = 9(1-x) miles
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Equation:
distance + distance = 6 miles
5x + 9(1-x) = 6
5x + 9-9x = 6
-4x = -3
x = 3/4 hr.
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Walk distance: 5x = 5(3/4) = 15/4 = 3 3/4 miles
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Cheers,
Stan H.
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