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Question 415595: what is the focal length of
(x − 4) ^2 /36 + (y + 5) ^2/ 25 = 1
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! what is the focal length of
(x − 4) ^2 /36 + (y + 5) ^2/ 25 = 1
..
(x−4)^2/36+(y+5)^2/25=1
This is an ellipse with centers at (4,-5) with horizontal major axis.
Standard form for this ellipse: (x-h)^2/a^2+(y-k)^2/b^2=1 with center at (h,k)
a^2=36
b^2=25
c^2=a^2-b^2
c=sqrt(36-25)=sqrt(11)
ans:
focal length of ellipse=sqrt(11)
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