SOLUTION: What is the smallest value assumed by the polynomial p(x) = 4x^2 - 3x + 8?
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Question 41555
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What is the smallest value assumed by the polynomial p(x) = 4x^2 - 3x + 8?
Answer by
Nate(3500)
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The vertex would give a result as the lowest value.
p(x) = 4x^2 - 3x + 8
((-b/2a),f(x))
((0.375),(7.4375))
0.375 would give you the lowest value for p(x).