SOLUTION: How do i find the remaining five trigonometric function values for Sin delta = 1/5 and delta is in the second quadrant? Thank you!
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Question 415480: How do i find the remaining five trigonometric function values for Sin delta = 1/5 and delta is in the second quadrant? Thank you! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How do i find the remaining five trigonometric function values for Sin delta = 1/5 and delta is in the second quadrant?
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sin = y/r = 1/5
So y = 1 and r = 5
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Solve for "x" in the 2nd Quadrant:
x = sqrt[5^2-1^2] = sqrt[24]
x = -2sqrt(6) in the 2nd Quadrant:
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sin = y/r = 1/5
cos = x/r = -2sqrt(6)/5
tan = y/x = 1/-2sqrt(6)
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csc = r/y = 5
sec = r/x = -5/(2sqrt(6))
cot = x/y = -2sqrt(6)
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Cheers,
Stan H.
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