SOLUTION: The stopping distance d of a car after the brakes are applied varies directly as the square speed r?
if a car traveling 30 mph can stop in 50 feet how many feet will it take the s
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-> SOLUTION: The stopping distance d of a car after the brakes are applied varies directly as the square speed r?
if a car traveling 30 mph can stop in 50 feet how many feet will it take the s
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Question 415241: The stopping distance d of a car after the brakes are applied varies directly as the square speed r?
if a car traveling 30 mph can stop in 50 feet how many feet will it take the same car to stop when it is traveling 90 mph?
You can put this solution on YOUR website! The stopping distance d of a car after the brakes are applied varies directly as the square speed r?
if a car traveling 30 mph can stop in 50 feet, how many feet will it take the same car to stop when it is traveling 90 mph?
:
Let k = constant of variation
:
d = k*r^2
When d = 50 and r = 30
k *30^2 = 50
900k = 50
k = 50/900
k = .0556
:
"how many feet will it take the same car to stop when it is traveling 90 mph?"
d = .0556 * 90^2
d = .0556 * 8100
d ~ 450 ft for a car going 90 mph to stop