SOLUTION: I need to know the steps for writing a polynomial as the product of two binomials. I would like to have four problems solved, with a step by step explanation for each. Thanks!

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Question 415164: I need to know the steps for writing a polynomial as the product of two binomials. I would like to have four problems solved, with a step by step explanation for each. Thanks!
6(3+r)+r(3+r)
d(d-5)+7(5-d)
(z-2)^2 +9(z-2)
4(z+1)^2 +3(z+1)

Thanks!

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
6(3+r)+r(3+r) is r^2 + 9r + 18 with corresponding factors (r+6)(r+3)
d(d-5)+7(5-d) is d^2 -12d + 35 with corresponding factors (d-7)(d-5)
(z-2)^2 +9(z-2) is z^2 + 5z -14 with corresponding factors (z+7)(z-2)
4(z+1)^2 +3(z+1)is 4z^2 + 11z +7 with corresponding factors (4z+7)(z+1)
Step by step on 1st one: the rest are completed in the same manner
6(3+r)+r(3+r) |Expanding in order to combine Like terms
18 + 6r + 3r + r^2 |combining Like terms
r^2 + 9r + 18 |factoring as a product of two binomials
(r + _)(r + _) What two numbers can we put in the blanks that have a product of 18 and a sum of 9??
(r+6)(r+3)
Note:SUM of the inner product(6r) and the outer product(3r) = 9r