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Question 415125: Factor fully:
a) x^3-27
b) 2x^3+4x^2-13x-6
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Factor fully:
a) x^3-27 = (x-3)(x^2+3x+9)
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b) 2x^3+4x^2-13x-6
x = 2 is a root
Use synthetic division to find the other two roots:
2)....2....4....-13....-6
.......2....8.....3....|..0
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Solve 2x^2+8x+3 = 0
x = [-8 +- sqrt(64-4*2*3)]/4
x = [-8 +- sqrt(40)]/4
x = [-8 +- 2sqrt(10)]/4
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x = -2+(1/2)sqrt(10) or x = -2-(1/2)sqrt(10)
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Cheers,
Stan H.
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