Question 414998: write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2)
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Standard form of the parabola: y=A(x-h)^2+k, with (h,k)= (x,y) coordinates of vertex, and A = coefficient of (x-h)^2. The problem in given case is to find A.
given parabola:
y=A(x+3)^2+6
using given point (1,-2),solve for A
-2=A(1+3)^2+6
-2=A(4^2)+6
-8=16A
A=-1/2
Equation of parabola:
y=-1/2(x+3)^2+6
The graph below is what the parabola looks like.
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