SOLUTION: solve log(base a)x= 2log (base a)3+ log(base a)5

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Question 414908: solve log(base a)x= 2log (base a)3+ log(base a)5
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log(base a)x= 2log (base a)^3 + log(base a)5
------
loga(x) = 3*2*1 + loga(5)
---
loga[x/5] = 6
---
x/5 = a^6
---
x = 5*a^6
=================
Cheers,
Stan H.
=================

Answer by MathTherapy(10699) About Me  (Show Source):
You can put this solution on YOUR website!
solve log(base a)x= 2log (base a)3+ log(base a)5

To this author, this equation is: log+%28a%2C+%28x%29%29+=+2%2Alog+%28a%2C+%283%29%29+%2B+log+%28a%2C+%285%29%29, and the answer, most defintely, 
is NOT x = 5*a^6, as the other person states.

log+%28a%2C+%28x%29%29+=+2%2Alog+%28a%2C+%283%29%29+%2B+log+%28a%2C+%285%29%29, with x > 0
log+%28a%2C+%28x%29%29+=+log+%28a%2C+%283%5E2%29%29+%2B+log+%28a%2C+%285%29%29 -- Applying d%2Alog+%28b%2C+%28c%29%29 = log+%28b%2C+%28c%5Ed%29%29
log+%28a%2C+%28x%29%29+=+log+%28a%2C+%283%5E2+%2A+5%29%29 --------- Applying log+%28b%2C%28c%29%29+%2B+log+%28b%2C+%28d%29%29 = log+%28b%2C+%28c%2Ad%29%29
log+%28a%2C+%28x%29%29+=+log+%28a%2C+%2845%29%29
     x = 45 ---- Applying c = d, if log+%28b%2C+%28c%29%29+=+log+%28b%2C+%28d%29%29