SOLUTION: My goal is to factor the polynomials: 8b^2+24b+18 Here is where I am at...and managing to confuse myself. 8b^2+24b+18 = GCF= 2: 8b^2/2 = (4b^2) and 24b/2 = (12b) and 18/

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: My goal is to factor the polynomials: 8b^2+24b+18 Here is where I am at...and managing to confuse myself. 8b^2+24b+18 = GCF= 2: 8b^2/2 = (4b^2) and 24b/2 = (12b) and 18/      Log On


   



Question 414907: My goal is to factor the polynomials:
8b^2+24b+18
Here is where I am at...and managing to confuse myself.
8b^2+24b+18 = GCF= 2: 8b^2/2 = (4b^2) and 24b/2 = (12b) and 18/2 = (9)
2(4b+12b+9) =
Please help!!!

Found 2 solutions by stanbon, sudhanshu_kmr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
factor the polynomials:
8b^2+24b+18
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= 2(4b^2+12b+9)
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= 2(2b+3)(2b+3)
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Cheers,
Stan H.
=========

Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

8b^2 + 24 b + 18
here 2 is common so, simplify it
= 2( 4b^2 + 12b + 9)
= 2( 4b^2 + 6b + 6b + 9 )
= 2( 2b(2b+3) + 3(2b+3))
= 2((2b+3) (2b+3))
= 2 (2b+3) (2b+3)

you can also factorize it as it is in form of a^2 +2ab+ b^2 = (a + b) ^2 , after second step....