SOLUTION: Find three consecutive integers such as the product of the first and the third exceeds the second by 19.

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Question 414714: Find three consecutive integers such as the product of the first and the third exceeds the second by 19.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x, (x+1) and (x+2) represent the three consecutive integers 

Note: As a preference is not stated in the question... 

these three consecutive integers can be either negative or positive integers.  

Question states***

 x(x+2) = (x+1) + 19

Solving for x

 x^2 +x -20 = 0

factoring

 (x+5)(x-4)= 0

 (x+5)= 0   x = -5   |the three consecutive integers are -5,-4,-3

 (x-4)= 0   x = 4    |the three consecutive integers are 4,5,6



CHECKING our Answer(s)***

 15 = -4 + 19

 24 = 5 + 19