Question 41470: Factor Completely
32aČ + 4a - 6
Answer by zeynep(43)   (Show Source):
You can put this solution on YOUR website! 32aČ + 4a - 6 LET's factor out 2 first;
2(16a^2+2a-3)
Now let's factor (16a^2+2a-3);
In the first term of the binomials, we need factors of 16a^2. This can be 2a and 8a.
In the second terms of the binomials, we need factors of -3. These can be 1 and -3.
So it becomes;
2(2a+1)(8a-3)
I hope this helps. If not, please do not hesitate to contact me!
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