SOLUTION: factor completely 4u^5+14u^4+10u^3

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Question 414572: factor completely
4u^5+14u^4+10u^3
Answer by lwsshak3(11628) About Me  (Show Source):
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factor completely
4u^5+14u^4+10u^3
..
4u^5+14u^4+10u^3
factor out 2u^3
(2u^3)(2u^2+7u+5)
(2u^3)(2u+5)(u+1)
2u^3=0
u=0 (multiplicity 3)
2u+5=0
u=-5/2
u+1=0
u=-1
ans:
zeros are:(0,0,0,-5/2,-1)