SOLUTION: Hello! I was absent from my algebra lesson, and I have a queston on my homework.It asks that I solve the equasion. The equasion is -2h^2-28h-98 . I know so far that I need to put i

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hello! I was absent from my algebra lesson, and I have a queston on my homework.It asks that I solve the equasion. The equasion is -2h^2-28h-98 . I know so far that I need to put i      Log On


   



Question 414527: Hello! I was absent from my algebra lesson, and I have a queston on my homework.It asks that I solve the equasion. The equasion is -2h^2-28h-98 . I know so far that I need to put it in two different sets of parenthasees. So far, all I have written down is (-h ) (h ). Please help me, because I am very confused. Thank you!
Found 3 solutions by jim_thompson5910, ankor@dixie-net.com, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

-2h%5E2-28h-98 Start with the given expression.


-2%28h%5E2%2B14h%2B49%29 Factor out the GCF -2.


Now let's try to factor the inner expression h%5E2%2B14h%2B49


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Looking at the expression h%5E2%2B14h%2B49, we can see that the first coefficient is 1, the second coefficient is 14, and the last term is 49.


Now multiply the first coefficient 1 by the last term 49 to get %281%29%2849%29=49.


Now the question is: what two whole numbers multiply to 49 (the previous product) and add to the second coefficient 14?


To find these two numbers, we need to list all of the factors of 49 (the previous product).


Factors of 49:
1,7,49
-1,-7,-49


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 49.
1*49 = 49
7*7 = 49
(-1)*(-49) = 49
(-7)*(-7) = 49

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 14:


First NumberSecond NumberSum
1491+49=50
777+7=14
-1-49-1+(-49)=-50
-7-7-7+(-7)=-14



From the table, we can see that the two numbers 7 and 7 add to 14 (the middle coefficient).


So the two numbers 7 and 7 both multiply to 49 and add to 14


Now replace the middle term 14h with 7h%2B7h. Remember, 7 and 7 add to 14. So this shows us that 7h%2B7h=14h.


h%5E2%2Bhighlight%287h%2B7h%29%2B49 Replace the second term 14h with 7h%2B7h.


%28h%5E2%2B7h%29%2B%287h%2B49%29 Group the terms into two pairs.


h%28h%2B7%29%2B%287h%2B49%29 Factor out the GCF h from the first group.


h%28h%2B7%29%2B7%28h%2B7%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28h%2B7%29%28h%2B7%29 Combine like terms. Or factor out the common term h%2B7


%28h%2B7%29%5E2 Condense the terms.


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So -2%28h%5E2%2B14h%2B49%29 then factors further to -2%28h%2B7%29%5E2


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Answer:


So -2h%5E2-28h-98 completely factors to -2%28h%2B7%29%5E2.


In other words, -2h%5E2-28h-98=-2%28h%2B7%29%5E2.


Note: you can check the answer by expanding -2%28h%2B7%29%5E2 to get -2h%5E2-28h-98 or by graphing the original expression and the answer (the two graphs should be identical).


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation: -2h^2 - 28h - 98 = 0
You can greatly simplify this be dividing both sides by -2, then you have
h^2 + 14h + 49 = 0
this easily factors to:
(h + 7)(h + 7) = 0
so we have
h = -7
:
:
Check this in the original equation
-2(-7^2) - 28(-7) - 98 = 0
-2(49) + 196 - 98
-98 + 196 - 98 = 0 confirms our solution of h = -7

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
What you missed is the factoring of the equation. In order to
factor it, you need to find the roots. the roots are where the
graph of the equation intersects the x-axis. That is also
where y+=+0, so I can say y+=+-2h%5E2-28h-98
Now set y+=+0
-2h%5E2-28h-98+=+0
Divide through by -2
h%5E2+%2B+14h+%2B+49+=+0
One way to factor this is with the quadratic formula
h+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Use this formula when the equation is in the form
ax%5E2+%2B+b%2Ax+%2B+c+=+0
a+=+1
b+=+14
c+=+49
Plug in these values:
h+=+%28-14+%2B-+sqrt%28+14%5E2-4%2A1%2A49+%29%29%2F%282%2A1%29+
h+=+%28-14+%2B-+sqrt%28+196+-+196+%29%29+%2F+2+
h+=+%28-14+%2B+0%29+%2F+2
h+=+-7
and also
h+=+%28-14+-+0%29+%2F+2
h+=+-7
In this case you have a double root, both are h+=+-7
I can write them as:
h+%2B+7+=+0
h+%2B+7+=+0
and
%28h+%2B+7%29%2A%28h+%2B+7%29+=+0
Multiplying out,
h%5E2+%2B+14h+%2B+49+=+0
So, I have found the 2 factors.
The graph of the equation is:
+graph%28+400%2C+400%2C+-12%2C+2%2C+-2%2C+10%2C+x%5E2+%2B+14x+%2B+49%29+