Question 414390: Find the area of polygon ABCD if the coordinates of the vertices are A(5,-1), B(9,2), C(9,9), and D(0,5).
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the area of polygon ABCD if the coordinates of the vertices are A(5,-1), B(9,2), C(9,9), and D(0,5).
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A - B - C- D-A
+5 +9 +9 +0 +5
-1 +2 +9 +5 -1
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Add diagonals from upper left
5*2 + 9*9 + 9*5 = 10 + 81 + 45 = 136
Add diagonals from lower left
-1*9 + 2*9 + 9*0 + 5*5 = -9 + 18 + 25 = 34
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Difference = 102
Area = 102/2 = 51 sq units
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PS It works for any # of points.
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