SOLUTION: Hello! I am having a lot of trouble with logs. I understand the rules for the most part. The problem is ( the 3 is a subscript) log<sub>3</sub>x = .24863 find square root o

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hello! I am having a lot of trouble with logs. I understand the rules for the most part. The problem is ( the 3 is a subscript) log<sub>3</sub>x = .24863 find square root o      Log On


   

Question 414318: Hello! I am having a lot of trouble with logs. I understand the rules for the most part.
The problem is ( the 3 is a subscript)
log3x = .24863 find square root of x
Found 2 solutions by ewatrrr, Edwin McCravy:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

If I am understanding Your question properly

 Log 3 x = .2486



   3^.2486 = x

find square root of x

 sqrt(3^.2486) =  1.1463

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
log3x = .24863 


You need the rule for changing a log equation to an
exponential equation and vice-versa:

That rule is this:

The logarithm equation:

logBA = C 

is equivalent to the exponential equation:

A = BC

So your logarithm equation 

log3x = .24863 is equivalent to

x = 3.24863

And you can do that with a calculator and get

x = 1.314094681

Then take the square root of that and get
 _
Öx = 1.146339688

Edwin