SOLUTION: if y varies inversely as the square root of x and y=27 when x=9, what is y when x=16? Find y in terms of x.
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Question 414296: if y varies inversely as the square root of x and y=27 when x=9, what is y when x=16? Find y in terms of x. Answer by ewatrrr(24785) (Show Source):
Hi
y varies inversely as the square root of x OR y =k/sqrt(x)
y=27 when x=9 27 = k/3 k = 81
what is y when x=16? Find y in terms of x.
y =k/sqrt(x)
y = 81/4 = 20.25