SOLUTION: find two consecutive odd integers such that 4 times the smaller is 9 more than 3 times the larger.

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Question 414250: find two consecutive odd integers such that 4 times the smaller is 9 more than 3 times the larger.
Answer by algebrahouse.com(1659) About Me  (Show Source):
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"find two consecutive odd integers such that 4 times the smaller is 9 more than 3 times the larger"

x = 1st consecutive odd integer
x + 2 = 2nd consecutive odd integer

4x = 3(x + 2) + 9 {4 times smaller is 9 more than 3 times larger}
4x = 3x + 6 + 9 {used distributive property}
4x = 3x + 15 {combined like terms}
x = 15 {subtracted 3x from both sides}
x + 2 = 17 {substituted 15, in for x, into x + 2}

15 and 17 are the two consecutive odd integers
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