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| Question 414169:  I was wondering if someone could tell me if I got these problems right? I am finding this to be a difficult subject.
 A pin consists of 2 letters followed by 3 numbers (assume repetition is allowed and order is important).
 a) how many different pin numbers are there?
 26*26*10*10*10=676,000
 b) what is the proabilty a pin number selected randomly ends in 000?
 26*26*9*9*9=492,804
 c)what is the probability a pin selected at random begins with AA?
 25*25*10*10*10=625,000
 d)what is the probability a pin selected at random being with A and ends with 00?
 25*26*10*9*9=526,500
 e)what is the probability a pin selected at random has a repeated letter and different numbers?
 26*25*10*9*8=468,000
 
 Thanks for your time and help,
 Gina
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! A pin consists of 2 letters followed by 3 numbers (assume repetition is allowed and order is important). a) how many different pin numbers are there?
 26*26*10*10*10=676,000
 b) what is the probabilty a pin number selected randomly ends in 000?
 26*26*9*9*9=492,804
 So probability = 492,804/676,000
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 c)what is the probability a pin selected at random begins with AA?
 25*25*10*10*10=625,000
 So probability = 625,000/676,000
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 d)what is the probability a pin selected at random begins with A and ends with 00?
 1*26*10*1*1=260
 So probability = 260/676,000
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 e)what is the probability a pin selected at random has a repeated letter and different numbers?
 That depends on the rules followed for building the pin.
 If repetition is allowed in building the pin the probability is 1.
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 Cheers,
 Stan H.
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