SOLUTION: If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16?      Log On


   

Question 41370This question is from textbook
: If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16? This question is from textbook

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16?
SINCE ALL ARE TO BASE 3,WE CAN DROP PUTTING THAT AND TAKE IT AS UNDERSTOOD.
LOG(16)=LOG(8*2)=LOG(8)+LOG(2)=1.8928+0.6309=2.5237
HENCE LOG(16) TO BASE 3 =2.5237