SOLUTION: for each parabola find the vertex, focus, and directrix.Then draw a graph (x-1)^2-2(y+1)=0

Algebra ->  Trigonometry-basics -> SOLUTION: for each parabola find the vertex, focus, and directrix.Then draw a graph (x-1)^2-2(y+1)=0      Log On


   

Question 413673: for each parabola find the vertex, focus, and directrix.Then draw a graph
(x-1)^2-2(y+1)=0
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where
the focus is (h,k + p)
%28x-1%29%5E2-2%28y%2B1%29=0
%28x-1%29%5E2=2%28y%2B1%29..........4p=2.....->+p=1%2F2
so,...->...the focus is (1, -1 + 1/2)............the focus is (1, -1/2)
and
the directrix is y = -1 - 1/2=-3/2.


+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+%28x-1%29%5E2-2%28y%2B1%29%29+