SOLUTION: At a candy store, there are 200 pieces of bubble gum in a bubble gum machine.
* Forty pieces are blue.
* Thirty-five pieces are red.
* Thirty pieces are green.
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-> SOLUTION: At a candy store, there are 200 pieces of bubble gum in a bubble gum machine.
* Forty pieces are blue.
* Thirty-five pieces are red.
* Thirty pieces are green.
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Question 412485: At a candy store, there are 200 pieces of bubble gum in a bubble gum machine.
* Forty pieces are blue.
* Thirty-five pieces are red.
* Thirty pieces are green.
* Fifty pieces are yellow.
* Forty-five pieces are white.
If four pieces of bubble gum are purchased, what is the probability of getting at least two pieces of red gum? Answer by ewatrrr(24785) (Show Source):
Hi
there are 200 pieces of bubble gum in a bubble gum machine of which:
* Forty pieces are blue.
* Thirty-five pieces are red* P(RED)= .175
* Thirty pieces are green.
* Fifty pieces are yellow.
* Forty-five pieces are white.
If four pieces of bubble gum are purchased...
Note: The probability of x successes in n trials is:
P = nCx* where p and q are the probabilities of success and failure respectively.
In this case p = .175 AND q = .825
nCx =
what is the probability of getting at least two pieces of red gum?
P(at least two pieces of red gum) = 1 - P(1) - P(0)
P = 1- 4(.175)*(.825)^3 - .825^4 = .1437
