SOLUTION: Given the equation above, where is the center of the conic section? (x+1)^2/16+(y-1)^2/16=1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Given the equation above, where is the center of the conic section? (x+1)^2/16+(y-1)^2/16=1      Log On


   

Question 412481: Given the equation above, where is the center of the conic section? (x+1)^2/16+(y-1)^2/16=1
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

%28x%2B1%29%5E2%2F16%2B%28y-1%29%5E2%2F16=1

%28x%2B1%29%5E2+%2B%28y-1%29%5E2=16  |Circlewith r = r and C(-1,1)

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




is the equation of a circle centered at and radius

Hint: Rewrite your equation as:




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