SOLUTION: given a normal distribution with a mean of 6000 and standard diviation 1500 what score is at the 30th percentile?

Algebra ->  Probability-and-statistics -> SOLUTION: given a normal distribution with a mean of 6000 and standard diviation 1500 what score is at the 30th percentile?      Log On


   

Question 412458: given a normal distribution with a mean of 6000 and standard diviation 1500 what score is at the 30th percentile?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

given a normal distribution with a mean of 6000 and standard diviation 1500

 what score is at the 30th percentile?

*Note: z+=+blue%28x+-+mu%29%2Fblue%28sigma%29

      -.5244 = (x -6000)/1500   |NORMSINV(0.3) = -.5244

     -.5244*1500 + 6000 = x = 5213.4