SOLUTION: Hi!
{{{f(x)= -(4/3)x^2 + 12x}}}
Can you prove that: if {{{ a<b<=9/2 }}} so we have {{{f(a)<f(b)}}}
Whith that, I'll determine the slope of the function.
I tried at fir
Algebra ->
Functions
-> SOLUTION: Hi!
{{{f(x)= -(4/3)x^2 + 12x}}}
Can you prove that: if {{{ a<b<=9/2 }}} so we have {{{f(a)<f(b)}}}
Whith that, I'll determine the slope of the function.
I tried at fir
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Question 412400: Hi!
Can you prove that: if so we have
Whith that, I'll determine the slope of the function.
I tried at first to calculate f(b)-f(a), but I don't know what to do after that...
Thank you and sorry for bad English.
You can put this solution on YOUR website! When , the function has a positive slope, since the vertex is at 9/2 and the x^2 coefficient is negative. We can say that the function is *strictly increasing* on this interval, so if , then .
