Question 41170: Solve b^4+2b^2-24=0
Answer by zeynep(43)   (Show Source):
You can put this solution on YOUR website! b^4+2b^2-24=0
let b^2 be t; then
b^4+2b^2-24=t^2+2t-24=0 (factor t^2+2t-24)
(t-4)(t+6)=0
t-4=0
t=4 and
t+6=0
t=-6 Since t=b^2
t=b^2 =4 so, b=2 and b=-2
t=b^2=-6 since square of a real number cannot be negative this equation has no solutions.
So, the solutions of this equation are 2 and -2.
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