SOLUTION: Hello, I solved this with prime numbers and it is a negative solution. Is this how I write the answer?
2y^2+3y+25=-2y^2+2y+15
4y^2+5y+40=0
-5+-sqrt((5)^2-4(4)(40))/(2(4))
-5
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Hello, I solved this with prime numbers and it is a negative solution. Is this how I write the answer?
2y^2+3y+25=-2y^2+2y+15
4y^2+5y+40=0
-5+-sqrt((5)^2-4(4)(40))/(2(4))
-5
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Question 411680: Hello, I solved this with prime numbers and it is a negative solution. Is this how I write the answer?
2y^2+3y+25=-2y^2+2y+15
4y^2+5y+40=0
-5+-sqrt((5)^2-4(4)(40))/(2(4))
-5+-sqrt(25-640)/(8)
-5+-sqrt(-615)/(8)
-5+-sqrt(3(205)i/(8)
-5+-sqrt(3(5)(41)i/(8)
-5+- i sqrt (3(5)(41)/(8)
