SOLUTION: Find the solution set in a +bi form: 6x^2 + 4x +1 =0
I tried and here is what I have so far then I'm lost.
Use the quadratic equation. The constants are a=6, b=4 and c=1.
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-> SOLUTION: Find the solution set in a +bi form: 6x^2 + 4x +1 =0
I tried and here is what I have so far then I'm lost.
Use the quadratic equation. The constants are a=6, b=4 and c=1.
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Question 411559: Find the solution set in a +bi form: 6x^2 + 4x +1 =0
I tried and here is what I have so far then I'm lost.
Use the quadratic equation. The constants are a=6, b=4 and c=1.
x = -b +/-sqrt(b^2-4ac)]/12
Thank you so much Found 2 solutions by ewatrrr, Alan3354:Answer by ewatrrr(24785) (Show Source):
Hi
Finding the solution set in a +bi form:
6x^2 + 4x +1 =0
a=6, b=4 and c=1 |Yes!
x = -b ± sqrt(b^2-4ac)]/12 |Yes! Finish substituting for b, b^2 and 4ac
x = -4 ± sqrt(16-24)]/12
x = -4 ± sqrt(-8)]/12
x = -4 ± sqrt(-1*4*2)]/12 |sqrt(-1) = i
x = -4 ± 2isqrt(2)]/12
x = -1/3 ± (1/6)isqrt(2)
x = -1/3 + (1/6)isqrt(2) x = -1/3 - (1/6)isqrt(2)
