SOLUTION: Solve equation and inequality. Use set builder notation or interval notation to write solution sets to the inequalities. (a) 18x^2 + 9x - 20 = 0 (b) 18x^2 + 9x - 20 (-/=)0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve equation and inequality. Use set builder notation or interval notation to write solution sets to the inequalities. (a) 18x^2 + 9x - 20 = 0 (b) 18x^2 + 9x - 20 (-/=)0       Log On


   



Question 411433: Solve equation and inequality. Use set builder notation or interval notation to write solution sets to the inequalities.
(a) 18x^2 + 9x - 20 = 0
(b) 18x^2 + 9x - 20 (-/=)0
(c) 18x^2 + 9x - 20 (+/=)0

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
18x%5E2%2B9x-20+=+0
To solve this equation we factor it (or use the Quadratic Formula). Factoring it we get:
(6x-5)(3x+4) = 0
From the Zero Product Property we know that one of these factors must be zero. So:
6x-5 = 0 or 4x+3 = 0
Solving each of these we get:
x+=+5%2F6 or x+=+-4%2F3

To solve the inequalities we will use the answers to the equation. When x+=+5%2F6 the factor (6x-5) is zero. When x is greater than 5/6, the factor will be larger than zero. (IOW: positive). And when x is less than 5/6 the factor willbe smaller than zero (negative). Using the same logic on the other factor we find that when x is larger than -4/3 the (4x+3) factor will be positive and when x is smaller than -4/3, that factor will be negative.

Now let's put this together. Think of a number line with the numbers -4/3 and 5/6 plotted. These two points divide the number line into three parts:
  • The part to the left of -4/3
  • The part to the right of 5/6
  • The part between -4/3 and 5/6

Let's analyze what each factor, (6x-5) and (4x+3), will be in each of these parts of the number line:
  • For x's to the left of -4/3, both factors will be negative. And since a negative times a negative is positive, (6x-5)(4x+3) will be positive.
  • For x's to the right of 5/6, both factors will be positive. And since a positive times a positive is positive, (6x-5)(4x+3) will be positive.
  • In between -4/3 and 5/6, (4x+3) will be positive and (6x-5) will be negative. And since a positive time a negative is negative, (6x-5)(4x+3) will be negative.

So we have found that if
x+%3C+-4%2F3 or x+%3E+6%2F5
then (6x-5)(4x+3) will be positive. If we include the values that make the factors zero we get:
x+%3C=+-4%2F3 or x+%3E=+6%2F5
This is the solution to 18x%5E2+%2B+9x+-+20+%3E=+0
In set notation this is {x | x+%3C=+-4%2F3 or x+%3E=+6%2F5}

And if
x+%3E+-4%2F3 and x+%3C+5%2F6
then (6x-5)(4x+3) will be negative. If we include the values that make the factors zero we get:
x+%3E=+-4%2F3 and x+%3C=+5%2F6
This is the solution to 18x%5E2+%2B+9x+-+20+%3C=+0

In set notation this is {x | x+%3E=+-4%2F3 and x+%3C=+5%2F6} or
{x | -4%2F3+%3C=+x+%3C=+5%2F6}