SOLUTION: solve by any method of your choice: 2x^2-3x=20

Algebra ->  Linear-equations -> SOLUTION: solve by any method of your choice: 2x^2-3x=20      Log On


   

Question 411292: solve by any method of your choice:
2x^2-3x=20
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

2x^2-3x=20

2x^2-3x-20=0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%283+%2B-+sqrt%28169+%29%29%2F%284%29+

  x = (3 ± 13)/4

  x = 4

  x = -10/4 = -5/2



CHECKING our Answer***

 (x-4)(x+5/2) = 0

 x%5E2+-%283%2F2%29x+-+20%2F2+=+0

 2x^2 -3x-20 = 0