SOLUTION: A plane took 1 hour longer to travel 560 miles on the first portion of the flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, w

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Question 41128: A plane took 1 hour longer to travel 560 miles on the first portion of the flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the seocnd part of the trip?
Is it 6 hours?

Answer by PaulAllen65270(19) About Me  (Show Source):
You can put this solution on YOUR website!
First you need to find the equation to work this problem
We will let the second planes flying time be equal to x
So if the first plane took 1 hour longer it would be x + 1
Now the formula to find speed is distance divided by time since the speeds are equal we need to find what that equation would be.
second planes speed is 480+%2F+x
The first planes speed is 560+%2F+%28x+%2B+1%29
The problem said that the speed was the same so now we can set these two equations equal to each other
480+%2F+x+=+560+%2F+%28x+%2B+1%29
You then need to cross multimply
480%2A%28x%2B1%29=560%2Ax
480x%2B480=560x
Then you subtract 480x from both sides
480=80x
Then you divide both sides by 80 to get x by itself
x=6
So the flight time of the second plane is 6 hours and the flight time of the other plane is 7 hours.