Question 410978: Hi there,
I was hoping you could help me figure out how to go about solving this problem:
"A B747 aircraft flew 6 hours with the wind. The return trip took 7 hours against the wind. If the speed of the plane im still air is 13 times the speed of the wind, find the wind speed and the speed of the plane in still air."
It was a question my entire math class was stuck on figuring out and it's been bothering me that we still can't get it.
Thanks
-S
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A B747 aircraft flew 6 hours with the wind.
The return trip took 7 hours against the wind.
If the speed of the plane in still air is 13 times the speed of the wind,
find the wind speed and the speed of the plane in still air."
:
I don't think you can know the actual speed of the wind and plane here, you need to know the distance.
:
Let x = speed of the wind
then
13x = speed of the plane in still air
:
The distance going and coming is equal, write a dist equation Dist = speed * time
6(13x + x) = 7(13x - x)
6(14x) = 7(12x)
84x = 84x
from this you can see that any value for x will satisfy, all you can know is
the relationship between the plane and the wind is 13:1
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