SOLUTION: FIVE liters of a 4% solution must be mixed with a 10% sloution to get a 6%solution. how many liters of the 10% are needed? thanks
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Question 41089: FIVE liters of a 4% solution must be mixed with a 10% sloution to get a 6%solution. how many liters of the 10% are needed? thanks Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Let x be the number of liters of 10% solution. The setup looks like this:
5(.04) + x(.10) = (5+x)(.06)
.2 + .1x = .3 + .06x
.04x = .1
x = 2.5 liters
