SOLUTION: LINK HAS 42 COINS CONSISTING OF NICKELS AND DIMES. IF THE TOTAL VALUE IS $3.30, FIND THE NUMBER OF EACH COIN.THANKS IM LEARING

Algebra ->  Linear-equations -> SOLUTION: LINK HAS 42 COINS CONSISTING OF NICKELS AND DIMES. IF THE TOTAL VALUE IS $3.30, FIND THE NUMBER OF EACH COIN.THANKS IM LEARING      Log On


   

Question 41088: LINK HAS 42 COINS CONSISTING OF NICKELS AND DIMES. IF THE TOTAL VALUE IS $3.30, FIND THE NUMBER OF EACH COIN.THANKS IM LEARING
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be the number of nickels, and then d will be the number of dimes. Their values will then be 5n and 10d respectively...then we have
5n + 10d = 330 (thinking in cents now)
n + d = 42
If we multiply the bottom one by 5 and subtract,
5n + 10d = 330
-(5n + 5d = 210)
we get
5d = 120
d = 24 and
n = 18
Check to see they add to $3.30...