SOLUTION: A man drive to a town at an average speed of 60 miles per hour. He returns by a road which is 10 miles shorter, at an average speed of 45 miles per hour. the return trip takes him
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Question 410841: A man drive to a town at an average speed of 60 miles per hour. He returns by a road which is 10 miles shorter, at an average speed of 45 miles per hour. the return trip takes him he same time as the first trip. Find the length of each road. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A man drive to a town at an average speed of 60 miles per hour.
He returns by a road which is 10 miles shorter, at an average speed of 45 miles per hour.
the return trip takes him he same time as the first trip.
Find the length of each road.
:
Let d = distance of the longer road
then
(d-10) = distance of the return road
:
Write a time equation: Time = dist/speed
:
To time = Return time =
Cross multiply
60(d-10) = 45d
60d - 600 = 45d
60d - 45d = 600
d =
d = 40 mi is the longer road, then obviously, 30 mi is the return road
:
:
Check this by finding the actual time of each trip, (they should be equal)
40/60 = .67 hr
30/45 = .67 hr also
