SOLUTION: write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b. (8,-5); 7x+3y=5. The equation of the line is y=?

Algebra ->  Graphs -> SOLUTION: write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b. (8,-5); 7x+3y=5. The equation of the line is y=?      Log On


   

Question 410614: write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b.
(8,-5); 7x+3y=5. The equation of the line is y=?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Line passing thru Pt(8,-5) and parallel to 7x + 3y = 5

 



 7x + 3y = 5  OR y = (-7/3)x + 5/3  |slope of these parallel lines is m =(-7/3)

New Line

  y = (-7/3)x + b  |using orderedpari Pt(8,-5) to solve for b

 -5 = (-7/3)*8 + b

 -40/8 + 56/8 = b

        2 = b

   y = (-7/3)x + 2  |y-intercept is Pt(0,2)