SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x)=2x^2-12x+20

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x)=2x^2-12x+20      Log On


   

Question 410585: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function
f(x)=2x^2-12x+20
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function

f(x)=2x^2-12x+20

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)=2(x^2-6x)+20   |completing square to put into vertex form

f(x)=2[(x-3)^2 - 9] +20

f(x) = 2(x-3)^2 -18 + 20

f(x) = 2(x-3)^2 + 2   |Vertex is Pt(3,2)  Line of symmetry is x= 3