SOLUTION: When the reciprocal of 3 times a number is subtracted from the reciprocal of the #, the result is one-sixth. find the number. Thank you

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: When the reciprocal of 3 times a number is subtracted from the reciprocal of the #, the result is one-sixth. find the number. Thank you      Log On


   

Question 41028: When the reciprocal of 3 times a number is subtracted from the reciprocal of the #, the result is one-sixth. find the number.
Thank you
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Try this:
1%2Fn+-+1%2F3n+=+1%2F6 Simplify.
%283-1%29%2F3n+=+1%2F6
2%2F3n+=+1%2F6 Multiply both sides by 3n.
2+=+3n%2F6 Multiply both sides by 6.
12+=+3n Finally, divide both sides by 3.
n+=+4
Check:
1%2F4+-+1%2F%283%2A4%29+=+1%2F6
1%2F4+-+1%2F12+=+1%2F6
3%2F12+-+1%2F12+=+1%2F6
2%2F12+=+1%2F6
1%2F6+=+1%2F6