SOLUTION: The sum of the digits of a two-digit number is 7. The number formed by reversing the digits is two more than double the original number. Find the original number.

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Question 409852: The sum of the digits of a two-digit number is 7. The number formed by reversing the digits is two more than double the original number. Find the original number.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the units digit = a
Let the tens digit = b
the number is: 10b+%2B+a
the number with reversed digits is: 10a+%2B+b
given:
(1) a+%2B+b+=+7
(2) 10a+%2B+b+=+2%2A%2810b+%2B+a%29+%2B+2
---------------------------
(2) 10a+%2B+b+=+20b+%2B+2a+%2B+2
(2) 8a+-+19b+=+2
Multiply both sides of (1) by 8
and subtract (1) from (2)
(2) 8a+-+19b+=+2
(1) -8a+-+8b+=+-56
-27b+=+-54
b+=+2
and, since
(1) a+%2B+b+=+7
a+=+5
The original number is 10b+%2B+a+ = 25
check answer:
(2) 10a+%2B+b+=+2%2A%2810b+%2B+a%29+%2B+2
(2) 10%2A5+%2B+2+=+2%2A%2810%2A2+%2B+5%29+%2B+2
(2) 52+=+2%2A25+%2B+2
(2) 52+=+52
OK