Question 409738: Can you please help with the following question?
Given Focus is (0,2) and Directrix is y=4, find the equation of the parabola.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Given Focus is (0,2) and Directrix is y=4, find the equation of the parabola.
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Since the directrix is above the focus, it is a parabola that opens downward with its axis of symmetry at x=0. The vertex is also on the axis of symmetry between the directrix and focus at (0,3) Its standard form is, (x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex, and p=1,the distance from vertex to focus or to directrix.
Equation of parabola:x^2=-4(y-3)
see graph below:
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y=(x^2-12)/-4
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