SOLUTION: find two numbers whose sum is -64, if twice the first is one more than the second.

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Question 409570: find two numbers whose sum is -64, if twice the first is one more than the second.
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find two numbers whose sum is -64,
if twice the first is one more than the second.
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Equations:
x + y = -64
2x = y+1
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Substitute for "x" and solve for "y":
2(-64-y) = y+1
-128-2y = y+1
3y = -129
y = -43
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Solve for "x":
x + y = -64
x - 43 = -64
x = -21
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Cheers,
Stan H.
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

twice the first number is one more than the second.

Let x and (2x -1)represent the first and  second number respectively

Question states***

 x + (2x -1)= -64

Solving for x

    3x = -63

     x = -21, the first number.  The second number is -43  (-42-1)

CHECKING our Answer***

 -21 + (-43) = -64