SOLUTION: Four years ago Melina was twice as old as Phoebe. In four years, Phoebe will be three-fourths of Melina's age. Find Melina and Phoebe's ages now.
Algebra ->
College
-> Linear Algebra
-> SOLUTION: Four years ago Melina was twice as old as Phoebe. In four years, Phoebe will be three-fourths of Melina's age. Find Melina and Phoebe's ages now.
Log On
Question 409569: Four years ago Melina was twice as old as Phoebe. In four years, Phoebe will be three-fourths of Melina's age. Find Melina and Phoebe's ages now. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Four years ago Melina was twice as old as Phoebe. In four years, Phoebe will be three-fourths of Melina's age. Find Melina and Phoebe's ages now.
-----------
Equations:
(m-4)= 2(p-4)
(p+4) = (3/4)(m+4)
---
Modify the 2nd equation:
4p+16 = 3m+12
-------------------------
Rearrange:
m-2p= -4
3m-4p= 4
-------------------
Modify:
3m-6p = -12
3m-4p = 4
----
Subtract and solve for "p":
2p = 16
p = 8
-----
Solve for "m":
m-2p = -4
m -2*8 = -4
m -16 = -4
m = 12
----------------------
Cheers,
Stan H.
================