SOLUTION: find three consecutive odd integers such that three times the first integer is one less than than the sum of the second and third integers

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Question 409316: find three consecutive odd integers such that three times the first integer is one less than than the sum of the second and third integers
Answer by peter_toribio90(6) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive odd integers:
x = first odd integer
x+%2B+2 = second odd integer
x+%2B+4 = third odd integer
3x+=+%28x+%2B+2%29+%2B+%28x+%2B+4%29+-+1
3x+=+2x+%2B+6+-+1
3x+=+2x+%2B+5
3x+-+2x+=+5
x+=+5
first odd integer = x+=+5
second odd integer = x+%2B+2+=+5+%2B+2+=+7
third odd intger = x+%2B+4+=+5+%2B+4+=+9
The three consecutive odd integers are 5, 7, and 9.
CHECK.
3x+=+%28x+%2B+2%29+%2B+%28x+%2B+4%29+-+1
3%285%29+=+7+%2B+9+-+1
15+=+15
God bless you! ;)