SOLUTION: The perimeter of a rectangle is 240 inches. The length of the rectangle is 4 times the width. Find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 240 inches. The length of the rectangle is 4 times the width. Find the dimensions of the rectangle.      Log On


   



Question 409315: The perimeter of a rectangle is 240 inches. The length of the rectangle is 4 times the width. Find the dimensions of the rectangle.
Answer by peter_toribio90(6) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 240 inches. The length of the rectangle is 4 times the width. Find the dimensions of the rectangle.
As geometry generally says, the formula for the perimeter of a rectangle is:
P+=+2l+%2B+2w
Since the length of the rectangle is 4 times the width, we say
l+=+4w
Now, by substitution of the given data, we get
240+=+2%284w%29+%2B+2w Notice that the length is replaced with 4w as a result of the equation above.
240+=+8w+%2B+2w Multiplication (2 x 4w = 8w).
240+=+10w Addition (8w + 2w = 10).
240%2F10+=+10w%2F10 Division on both sides.
w+=+24 Result. (240/10 = 24)
***Since we now have the value of w (width), all we need to do is substitute it to the formula l = 4w (above).
l+=+4w
l+=+4%2824%29
l+=+96
==================
The dimension are:
length = 96
width = 24
==================
CHECK:
P+=+2l+%2B+2w
240+=+2%2896%29+%2B+2%2824%29
240+=+192+%2B+48
240+=+240