SOLUTION: Hi, I am solving with the quadraic formula and would like you to check my work and answer please. 3n^2-2n+5=0 -2 sqrt ((-2)^2-4(3)(5))/(2(3)) -2 sqrt (4-60)/(2) -2 sqrt (60

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hi, I am solving with the quadraic formula and would like you to check my work and answer please. 3n^2-2n+5=0 -2 sqrt ((-2)^2-4(3)(5))/(2(3)) -2 sqrt (4-60)/(2) -2 sqrt (60      Log On


   



Question 409257: Hi, I am solving with the quadraic formula and would like you to check my work and answer please.
3n^2-2n+5=0
-2 sqrt ((-2)^2-4(3)(5))/(2(3))
-2 sqrt (4-60)/(2)
-2 sqrt (60)/(2)
-2 sqrt ((4)(15))/(2)
-2 +- 2 sqrt (15)/(2) is this final answer?

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

3n%5E2-2n%2B5=0 Start with the given equation.


Notice we have a quadratic equation in the form of an%5E2%2Bbn%2Bc where a=3, b=-2, and c=5


Let's use the quadratic formula to solve for n


n+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


n+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%283%29%285%29+%29%29%2F%282%283%29%29 Plug in a=3, b=-2, and c=5


n+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%283%29%285%29+%29%29%2F%282%283%29%29 Negate -2 to get 2.


n+=+%282+%2B-+sqrt%28+4-4%283%29%285%29+%29%29%2F%282%283%29%29 Square -2 to get 4.


n+=+%282+%2B-+sqrt%28+4-60+%29%29%2F%282%283%29%29 Multiply 4%283%29%285%29 to get 60


n+=+%282+%2B-+sqrt%28+-56+%29%29%2F%282%283%29%29 Subtract 60 from 4 to get -56


n+=+%282+%2B-+sqrt%28+-56+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


n+=+%282+%2B-+2i%2Asqrt%2814%29%29%2F%286%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


n+=+%282%2B2i%2Asqrt%2814%29%29%2F%286%29 or n+=+%282-2i%2Asqrt%2814%29%29%2F%286%29 Break up the expression.


n+=+%281%2Bi%2Asqrt%2814%29%29%2F%283%29 or n+=+%281-i%2Asqrt%2814%29%29%2F%283%29 Reduce


So the answers are n+=+%281%2Bi%2Asqrt%2814%29%29%2F%283%29 or n+=+%281-i%2Asqrt%2814%29%29%2F%283%29


If you need more help, email me at jim_thompson5910@hotmail.com

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Jim