Question 409158: hi, I am solving by quadraic formula -b sqrt (b2-4ac)/(2a)
x^2+2x=168
x^2+2x-168=168-168
x^2+2x-168=0
-2 +- sqrt (2^2-4(1)(-168)/(2(1))
-2 +- sqrt (4-672)/(2)
-2 +- sqrt (668)/(2) This is where I am lost. It's not a perfect square, so
what do I do now? I choose factors.
-2 +- sqrt ((4(167))/(2)
-2 +- 2 sqrt (167)/(2)
common denominator of 2
-1 sqrt(167)/(2)
Would you help me understand where I went wrong and how to do it right? Answer by solver91311(24713) (Show Source):
