SOLUTION: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the orginal solution must be drained off and replaced by pure antifreeze to make a 25% soluti

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Question 408969: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the orginal solution must be drained off and replaced by pure antifreeze to make a 25% solution of antifreeze?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Let x represent the amount drained off and replaced
Question states***
.20(16qt-x) + 1*x = .25*16qt
Solving for x
.8x = .05*16qt
x = 1qt, needs to be drained off and replaced with pure antifreeze
CHECKING our Answer***
.20*15 + 1 = 4 = .25*16